What is the maximum mass of h2o that can be produced by combining?

hydrogen and oxygen gas.

The maximum mass of H2O that can be produced by combining hydrogen and oxygen gas is determined by the law of conservation of mass. According to this law, the total mass of reactants must be equal to the total mass of products in a chemical reaction.

The chemical equation for the reaction between hydrogen and oxygen gas to produce water is:

2H2 + O2 → 2H2O

This means that two molecules of hydrogen gas (H2) combine with one molecule of oxygen gas (O2) to produce two molecules of water (H2O).

The molar masses of hydrogen gas (H2) and oxygen gas (O2) are 2.02 g/mol and 32.00 g/mol, respectively. The molar mass of water (H2O) is 18.02 g/mol.

To calculate the maximum mass of H2O that can be produced from a given amount of hydrogen and oxygen gas, we need to use the stoichiometry of the equation. This means that we need to determine the limiting reagent, which is the reactant that is consumed first and limits the amount of product that can be formed.

For example, if we have 4 grams of hydrogen gas and 32 grams of oxygen gas, we can calculate the maximum mass of water that can be produced as follows:

1. Convert grams to moles: 4 g H2 x (1 mol H2 / 2.02 g H2) = 1.98 mol H2 32 g O2 x (1 mol O2 / 32.00 g O2) = 1 mol O2

2. Determine limiting reagent: Since we need 2 moles of H2 for every 1 mole of O2, we can see that we have an excess of O2. Therefore, O2 is the limiting reagent.

3. Calculate maximum mass of H2O: 1 mol O2 x (2 mol H2O / 1 mol O2) x (18.02 g H2O / 1 mol H2O) = 36.04 g H2O

Therefore, the maximum mass of H2O that can be produced from 4 grams of H2 and 32 grams of O2 is 36.04 grams.